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標題:
maths
發問:
solve (1/x)+(1/y)= 6 (1/x)-(1/y)= -2 x=? y=?
(1/x)+(1/y)= 6------(1) (1/x)-(1/y)= -2--------(2) (1) + (2) 2/x = 4 x = 1/2 Substitue x = 1/2 into (1) [1/(1/2)] + (1/y) = 6 2 + (1/y) = 6 1/y = 4 y = 1/4
其他解答:
(1/x)-(1/y)= -2 (1/x) = (1/y)-2...(1) Substitute (1/x) = (1/y)-2 into (1/x)+(1/y)= 6 (1/y)-2+(1/y)= 6 2/y = 8 y = 1/4 substitute y = 1/4 into (1) 1/x = 1/(1/4) -2 1/x = 4-2 1/x = 2 x=1/2
maths
發問:
solve (1/x)+(1/y)= 6 (1/x)-(1/y)= -2 x=? y=?
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最佳解答:(1/x)+(1/y)= 6------(1) (1/x)-(1/y)= -2--------(2) (1) + (2) 2/x = 4 x = 1/2 Substitue x = 1/2 into (1) [1/(1/2)] + (1/y) = 6 2 + (1/y) = 6 1/y = 4 y = 1/4
其他解答:
(1/x)-(1/y)= -2 (1/x) = (1/y)-2...(1) Substitute (1/x) = (1/y)-2 into (1/x)+(1/y)= 6 (1/y)-2+(1/y)= 6 2/y = 8 y = 1/4 substitute y = 1/4 into (1) 1/x = 1/(1/4) -2 1/x = 4-2 1/x = 2 x=1/2
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