f.1 maths－wszspj2的部落格

標題:

f.1 maths

發問:

7[2(x-3)=x]=4[1-3(x+2)] 3[7-4(c-2)]=41 唔該要有steps

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最佳解答:

7[2(x-3)+x] = 4[1-3(x+2)] 7[2x-6+x] = 4[1-3x-6] 14x-42+7x = 4-12x-24 21x-42 = -20-12x 21x+12x = -20+42 33x = 22 x = 22/33 x = 2/3 3[7-4(c-2)] = 41 3[7-4c+8] = 41 3[15-4c] = 41 45-12c = 41 -12c = 41-45 -12c = -4 -c = -4/12 -c = -(1/3) c = 1/3 希望可以幫到你~

其他解答:

7[2(x-3)+x]=4[1-3(x+2)] 7[2x-6+x] = 4[1-3x-6] 14x-42+7x = 4-12x-24 21x-42 = -12x-28 21x+12x = 42-28 33x = 14 x = 14/33 = 0.424242 3[7-4(c-2)]=41 3[7-4c+8] = 41 3[15-4c] = 41 45-12c = 41 45-41 = 12c c = 4/12 = 1/3 = 0.333|||||點解第一條有兩個 '='? 係唔係打錯o左? 3[7-4(c-2)]=41 3[7-4c+8]=41 3[15-4c]=41 45-12c=41 4=12c c=1/3|||||7[2(x-3)=x]=4[1-3(x+2)] something wrong in your Q, pls. re-post 3[7-4(c-2)]=41 3[7-4c+8] = 41 21-12c+24 = 41 -12c = 41-21-24 -12c = -4 c = 1/3 = 0.3333|||||3[7-4(c-2)]=41 3(7-4c+8)=41 21-12c+24=41 -12c=-4 c=1/3 7[2(x-3)=x]=4[1-3(x+2)] 以上果題有少少問題，睇吓自己有冇打錯。 2008-01-29 12:24:39 補充：我想那個=是-我試試看7[2(x-3)=x]=4[1-3(x 2)] 7(2x-6-x)=4(1-3x 6) 14x-42-7x=4-12x 24 7x-42=28-12x 19x=70 x=3.68(兩個小數位)