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幫我翻譯英文.......(20點)
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第一個Priority (0-240) Defines the priority for the use of a port in the STA algorithm. If the path cost for all ports on a switch are the same, the port with the highest priority (i.e., lowest value) will be configured as an active link in the Spanning Tree. Where more than one port is assigned the highest... 顯示更多 第一個 Priority (0-240) Defines the priority for the use of a port in the STA algorithm. If the path cost for all ports on a switch are the same, the port with the highest priority (i.e., lowest value) will be configured as an active link in the Spanning Tree. Where more than one port is assigned the highest priority, the port with lowest numeric identifier will be enabled. Range: 0-240, in steps of 16 Default: 128 第2個 Path Cost (1-200000000) This parameter is used by the STA to determine the best path between devices. Therefore, lower values should be assigned to ports attached to faster media, and higher values assigned to ports with slower media. (Path cost takes precedence over port priority.) Note that when the Path Cost Method is set to short, the maximum path cost is 65,535. Range: 1-200000000 Default: 1000000
最佳解答:
1.優先（0-240) 在 STA 運算法則中為港口的使用定義優先。 如果對於在一個開關上的所有的港口路徑費用是一樣的，和最高的優先 （也就是，最低的價值）的港口將在跨越樹中被配置如一個積極的連結。 在超過一港口被分配最高的優先的地方，和最低的數值標識符的港口將被能夠。 範圍： 0-240, 在步驟中 16 假設值： 128 2.路徑費用（1-200000000) 這一個參數被 STA 使用在裝置之間決定最好的路徑。 因此，更低的價值應該被指定給對更快速的媒體的港口附件，而且更高的價值分配到和更慢的媒體的港口。 （路徑費用在港口優先之上領先．) 注意，當路徑費用方法被設定成短的時候，最大的路徑費用是 65,535 。 範圍： 1-200000000 假設值： 1000000 我是用翻譯機翻ㄉ^^"可是我絕ㄉ看起來有一點怪怪ㄉ...
第一個: Defines the priority for the use of a port in the STA algorithm. If the path cost for all ports on a switch are the same, the port with the highest priority (i.e., lowest value) will be configured as an active link in the Spanning Tree. Where more than one port is assigned the highest priority, the port with lowest numeric identifier will be enabled. Range: 0-240, in steps of 16 定義優先權至於對一個口岸的使用在STA 算法。 如果道路花費為所有口岸在開關是相同, 口岸以重要性(i.e., 最低值的) 將被配置作為一個活躍鏈接在生成樹。 那裡超過一個口岸被分配重要性, 口岸與最低的數字標識符將使能。 第二個: This parameter is used by the STA to determine the best path between devices. Therefore, lower values should be assigned to ports attached to faster media, and higher values assigned to ports with slower media. (Path cost takes precedence over port priority.) Note that when the Path Cost Method is set to short, the maximum path cost is 65,535. 這個參量由STA 使用確定最佳的道路在設備之間。 所以, 更加低值的應該被賦予到口岸附有更加快速的媒介, 並且上限值分配了到口岸以更加緩慢的媒介。 (道路費用比港優先權優先。) 筆記當道路費用方法被設置對短小, 最大道路費用是65,535 。73E3DC9315AE223D
幫我翻譯英文.......(20點)
發問:
第一個Priority (0-240) Defines the priority for the use of a port in the STA algorithm. If the path cost for all ports on a switch are the same, the port with the highest priority (i.e., lowest value) will be configured as an active link in the Spanning Tree. Where more than one port is assigned the highest... 顯示更多 第一個 Priority (0-240) Defines the priority for the use of a port in the STA algorithm. If the path cost for all ports on a switch are the same, the port with the highest priority (i.e., lowest value) will be configured as an active link in the Spanning Tree. Where more than one port is assigned the highest priority, the port with lowest numeric identifier will be enabled. Range: 0-240, in steps of 16 Default: 128 第2個 Path Cost (1-200000000) This parameter is used by the STA to determine the best path between devices. Therefore, lower values should be assigned to ports attached to faster media, and higher values assigned to ports with slower media. (Path cost takes precedence over port priority.) Note that when the Path Cost Method is set to short, the maximum path cost is 65,535. Range: 1-200000000 Default: 1000000
最佳解答:
1.優先（0-240) 在 STA 運算法則中為港口的使用定義優先。 如果對於在一個開關上的所有的港口路徑費用是一樣的，和最高的優先 （也就是，最低的價值）的港口將在跨越樹中被配置如一個積極的連結。 在超過一港口被分配最高的優先的地方，和最低的數值標識符的港口將被能夠。 範圍： 0-240, 在步驟中 16 假設值： 128 2.路徑費用（1-200000000) 這一個參數被 STA 使用在裝置之間決定最好的路徑。 因此，更低的價值應該被指定給對更快速的媒體的港口附件，而且更高的價值分配到和更慢的媒體的港口。 （路徑費用在港口優先之上領先．) 注意，當路徑費用方法被設定成短的時候，最大的路徑費用是 65,535 。 範圍： 1-200000000 假設值： 1000000 我是用翻譯機翻ㄉ^^"可是我絕ㄉ看起來有一點怪怪ㄉ...
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其他解答:第一個: Defines the priority for the use of a port in the STA algorithm. If the path cost for all ports on a switch are the same, the port with the highest priority (i.e., lowest value) will be configured as an active link in the Spanning Tree. Where more than one port is assigned the highest priority, the port with lowest numeric identifier will be enabled. Range: 0-240, in steps of 16 定義優先權至於對一個口岸的使用在STA 算法。 如果道路花費為所有口岸在開關是相同, 口岸以重要性(i.e., 最低值的) 將被配置作為一個活躍鏈接在生成樹。 那裡超過一個口岸被分配重要性, 口岸與最低的數字標識符將使能。 第二個: This parameter is used by the STA to determine the best path between devices. Therefore, lower values should be assigned to ports attached to faster media, and higher values assigned to ports with slower media. (Path cost takes precedence over port priority.) Note that when the Path Cost Method is set to short, the maximum path cost is 65,535. 這個參量由STA 使用確定最佳的道路在設備之間。 所以, 更加低值的應該被賦予到口岸附有更加快速的媒介, 並且上限值分配了到口岸以更加緩慢的媒介。 (道路費用比港優先權優先。) 筆記當道路費用方法被設置對短小, 最大道路費用是65,535 。73E3DC9315AE223D
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